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📚 Definition of Verifying Solutions by Substitution
Verifying solutions by substitution is a fundamental technique in algebra used to check whether a given value for a variable satisfies a particular equation. It involves replacing the variable in the equation with the proposed solution and then simplifying both sides of the equation. If the left-hand side (LHS) equals the right-hand side (RHS) after the substitution, the proposed solution is correct. If LHS ≠ RHS, the proposed solution is incorrect.
📜 History and Background
The concept of verifying solutions is deeply rooted in the history of algebra. Early mathematicians recognized the importance of confirming the validity of their solutions to equations. While the explicit term "verifying solutions by substitution" might not appear in ancient texts, the underlying principle was practiced. Over centuries, algebraic notation and techniques evolved, making substitution a more formalized and efficient method. The development of symbolic algebra in the 16th and 17th centuries, particularly by mathematicians like François Viète and René Descartes, greatly contributed to the standardization of algebraic practices, including solution verification.
🔑 Key Principles of Verification by Substitution
- 🔍 Identify the Equation and Proposed Solution: Start with the algebraic equation you want to verify, such as $2x + 3 = 7$, and the proposed solution, such as $x = 2$.
- 🔄 Substitute: Replace every instance of the variable in the equation with the proposed solution. For example, if the equation is $2x + 3 = 7$ and the proposed solution is $x = 2$, the substitution yields $2(2) + 3 = 7$.
- ➗ Simplify: Perform the arithmetic operations on both sides of the equation separately. In the example above, simplify $2(2) + 3$ to get $4 + 3 = 7$, which simplifies further to $7 = 7$.
- ✅ Check for Equality: Compare the simplified left-hand side (LHS) and right-hand side (RHS) of the equation. If LHS = RHS, the proposed solution is correct. If LHS ≠ RHS, the proposed solution is incorrect. In the example, $7 = 7$, so the proposed solution $x = 2$ is correct.
➕ Real-World Examples
Example 1: Simple Linear Equation
Equation: $3x - 5 = 10$
Proposed Solution: $x = 5$
Substitution: $3(5) - 5 = 10$
Simplification: $15 - 5 = 10$
Result: $10 = 10$ (Correct)
Example 2: Quadratic Equation
Equation: $x^2 - 4x + 3 = 0$
Proposed Solution: $x = 1$
Substitution: $(1)^2 - 4(1) + 3 = 0$
Simplification: $1 - 4 + 3 = 0$
Result: $0 = 0$ (Correct)
Example 3: Equation with Fractions
Equation: $\frac{x}{2} + 1 = 4$
Proposed Solution: $x = 6$
Substitution: $\frac{6}{2} + 1 = 4$
Simplification: $3 + 1 = 4$
Result: $4 = 4$ (Correct)
Example 4: Equation with Exponents
Equation: $2^x = 8$
Proposed Solution: $x = 3$
Substitution: $2^3 = 8$
Simplification: $8 = 8$
Result: $8 = 8$ (Correct)
Example 5: Linear Equation with Two Variables
Equation: $x + y = 5$
Proposed Solution: $x = 2, y = 3$
Substitution: $2 + 3 = 5$
Simplification: $5 = 5$
Result: $5 = 5$ (Correct)
Example 6: Incorrect Solution
Equation: $4x + 2 = 10$
Proposed Solution: $x = 1$
Substitution: $4(1) + 2 = 10$
Simplification: $4 + 2 = 10$
Result: $6 = 10$ (Incorrect)
Example 7: More Complex Equation
Equation: $2(x + 1) = 6$
Proposed Solution: $x = 2$
Substitution: $2(2 + 1) = 6$
Simplification: $2(3) = 6$
Result: $6 = 6$ (Correct)
📝 Conclusion
Verifying solutions by substitution is a powerful and essential technique in algebra. It ensures the accuracy of solutions and reinforces understanding of algebraic principles. By systematically substituting proposed solutions and checking for equality, students and practitioners can confidently validate their work and build a solid foundation in algebra.
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