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brooke_sandoval Jan 21, 2026 โ€ข 0 views

Steps to prove the Sturm Separation Theorem for second-order ODEs.

Hey! ๐Ÿ‘‹ Struggling with the Sturm Separation Theorem? It can be a tricky one. I'll walk you through the steps in a way that (hopefully!) makes sense. Let's get this theorem demystified together! ๐Ÿค“
๐Ÿงฎ Mathematics

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โœ… Best Answer

๐Ÿ“š What is the Sturm Separation Theorem?

The Sturm Separation Theorem is a powerful result in the study of second-order linear homogeneous ordinary differential equations (ODEs). It tells us about the oscillatory behavior of solutions, specifically how the zeros (or roots) of linearly independent solutions are intertwined.

๐Ÿ“œ Historical Background

The theorem is named after Jacques Charles Franรงois Sturm, a 19th-century mathematician who made significant contributions to various areas of mathematics, including differential equations. His work laid the foundation for understanding the qualitative behavior of solutions to ODEs.

๐Ÿ”‘ Key Principles and Assumptions

The Sturm Separation Theorem applies to second-order linear homogeneous ODEs of the form:

$- (p(x)y')' + q(x)y = 0$,

or equivalently,

$p(x)y'' + p'(x)y' + q(x)y = 0$,

where $p(x) > 0$ and $p(x)$, $p'(x)$, and $q(x)$ are continuous on the interval of interest.

๐Ÿ“ Steps to Prove the Sturm Separation Theorem

Here's a breakdown of the steps involved in proving the theorem:

1๏ธโƒฃ ๐Ÿš€ Start with the ODE:

  • ๐Ÿ” Consider the second-order linear homogeneous ODE: $p(x)y'' + p'(x)y' + q(x)y = 0$
  • ๐Ÿ“– Assume $p(x) > 0$ and that $p(x)$, $p'(x)$, and $q(x)$ are continuous on the interval $[a, b]$.

2๏ธโƒฃ ๐Ÿงฌ Define Linearly Independent Solutions:

  • ๐Ÿ”ฌ Let $y_1(x)$ and $y_2(x)$ be two linearly independent solutions of the given ODE.
  • ๐Ÿงช This means that no constant $c$ exists such that $y_1(x) = c y_2(x)$ for all $x$ in $[a, b]$.

3๏ธโƒฃ ๐Ÿ”ข Assume $y_1(x)$ has Consecutive Zeros:

  • ๐Ÿ“Š Suppose $y_1(x)$ has two consecutive zeros at $x_1$ and $x_2$ in the interval $[a, b]$, where $x_1 < x_2$. This means $y_1(x_1) = 0$ and $y_1(x_2) = 0$.

4๏ธโƒฃ ๐ŸŒ Show $y_2(x)$ has a Zero between $x_1$ and $x_2$:

  • ๐Ÿ’ก We want to prove that $y_2(x)$ must have at least one zero in the open interval $(x_1, x_2)$. We proceed by contradiction.
  • ๐Ÿšซ Assume $y_2(x)$ has no zeros in $(x_1, x_2)$. This means $y_2(x) > 0$ or $y_2(x) < 0$ for all $x$ in $(x_1, x_2)$. Without loss of generality, assume $y_2(x) > 0$ in $(x_1, x_2)$.

5๏ธโƒฃ โœ๏ธ Use Abel's Identity (Wronskian):

  • ๐Ÿ“ The Wronskian of two solutions $y_1(x)$ and $y_2(x)$ is defined as $W(x) = y_1(x)y_2'(x) - y_1'(x)y_2(x)$.
  • ๐Ÿ”‘ Abel's Identity states that $W(x) = C/p(x)$ for some constant $C$, where $p(x)$ is the coefficient from the ODE. Since $y_1$ and $y_2$ are linearly independent, $C \neq 0$.

6๏ธโƒฃ ๐Ÿ“ˆ Evaluate the Wronskian at $x_1$ and $x_2$:

  • ๐Ÿ“Œ At $x_1$, $W(x_1) = y_1(x_1)y_2'(x_1) - y_1'(x_1)y_2(x_1) = -y_1'(x_1)y_2(x_1)$.
  • ๐Ÿ“ At $x_2$, $W(x_2) = y_1(x_2)y_2'(x_2) - y_1'(x_2)y_2(x_2) = -y_1'(x_2)y_2(x_2)$.

7๏ธโƒฃ ๐Ÿงฎ Analyze the Signs:

  • โœ… Since $y_2(x) > 0$ in $(x_1, x_2)$, $y_2(x_1) \geq 0$ and $y_2(x_2) \geq 0$. Also, since $y_1(x_1) = y_1(x_2) = 0$ and $y_1(x)$ changes sign at $x_1$ and $x_2$, $y_1'(x_1)$ and $y_1'(x_2)$ have opposite signs.
  • โž— Therefore, $W(x_1)$ and $W(x_2)$ have the same sign.
  • โž– This implies that $C/p(x_1)$ and $C/p(x_2)$ have the same sign. Since $p(x) > 0$, $C$ must have the same sign at both points.

8๏ธโƒฃ โ— Derive the Contradiction:

  • ๐Ÿ”ฅ However, since $W(x) = C/p(x)$, and $C$ is a nonzero constant, $W(x)$ has a constant sign. But the Wronskian also equals $-y_1'(x)y_2(x)$ evaluated at $x_1$ and $x_2$. Since $y_1'(x_1)$ and $y_1'(x_2)$ have opposite signs, the Wronskian *must* change sign between $x_1$ and $x_2$, which is a contradiction!

9๏ธโƒฃ ๐ŸŽ‰ Conclude the Proof:

  • ๐ŸŽˆ Therefore, our assumption that $y_2(x)$ has no zeros in $(x_1, x_2)$ must be false. Hence, $y_2(x)$ must have at least one zero in the interval $(x_1, x_2)$. This completes the proof of the Sturm Separation Theorem.

๐Ÿ’ก Real-World Examples

The Sturm Separation Theorem is vital in the analysis of physical systems described by ODEs, such as:

  • ๐ŸŽป Vibration analysis: Understanding the modes of vibration of a string.
  • โš›๏ธ Quantum mechanics: Analyzing the behavior of wave functions in quantum systems.
  • ๐ŸŒŠ Wave propagation: Studying the propagation of waves in various media.

โญ Conclusion

The Sturm Separation Theorem provides a fundamental understanding of the oscillatory behavior of solutions to second-order linear homogeneous ODEs. It showcases the intertwined nature of the zeros of linearly independent solutions and has broad applications in physics and engineering.

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