steven500
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Solved Examples: Finding and Classifying Equilibrium Points in ODEs

Hey there! 👋 Struggling with finding and classifying equilibrium points in ODEs? Don't worry, I've got you covered! Check out this quick study guide and practice quiz to boost your skills. Let's get started! 🚀
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adam307 Jan 1, 2026

📚 Quick Study Guide

  • 🔍 Equilibrium Points: Equilibrium points, also known as critical points or stationary points, are the values of $y$ for which $\frac{dy}{dt} = 0$. These points represent constant solutions to the differential equation.
  • 📈 Finding Equilibrium Points: To find equilibrium points, set the differential equation equal to zero and solve for $y$. For example, given $\frac{dy}{dt} = f(y)$, solve $f(y) = 0$.
  • 📊 Classifying Equilibrium Points: Equilibrium points can be classified as stable, unstable, or semi-stable. This classification depends on the behavior of solutions near the equilibrium point.
  • ➡️ Stability Analysis:
    • Stable: Solutions near the equilibrium point converge towards it as $t$ increases.
    • Unstable: Solutions near the equilibrium point move away from it as $t$ increases.
    • Semi-stable: Solutions approach the equilibrium point from one side but move away from it from the other side.
  • 🧪 Using the Sign of $\frac{dy}{dt}$:
    • If $\frac{dy}{dt} > 0$ for $y < y_e$ and $\frac{dy}{dt} < 0$ for $y > y_e$, then $y_e$ is stable.
    • If $\frac{dy}{dt} < 0$ for $y < y_e$ and $\frac{dy}{dt} > 0$ for $y > y_e$, then $y_e$ is unstable.
    • If $\frac{dy}{dt}$ has the same sign on both sides of $y_e$, then $y_e$ is semi-stable.
  • 📝 Linearization (Advanced): For more complex systems, linearization around the equilibrium point can be used to determine stability. Calculate the Jacobian matrix and analyze its eigenvalues.

Practice Quiz

  1. Consider the differential equation $\frac{dy}{dt} = y(y-2)$. Which of the following are the equilibrium points?

    1. $y = 0$ only
    2. $y = 2$ only
    3. $y = 0$ and $y = 2$
    4. $y = -2$ and $y = 2$
  2. For the differential equation $\frac{dy}{dt} = y - y^2$, classify the stability of the equilibrium point $y = 0$.

    1. Stable
    2. Unstable
    3. Semi-stable
    4. Cannot be determined
  3. Given $\frac{dy}{dt} = (y-1)(y-3)$, classify the stability of $y=1$.

    1. Stable
    2. Unstable
    3. Semi-stable
    4. Asymptotically stable
  4. Which of the following differential equations has equilibrium points at $y = -1$ and $y = 1$?

    1. $\frac{dy}{dt} = y^2 - 1$
    2. $\frac{dy}{dt} = y^2 + 1$
    3. $\frac{dy}{dt} = y - 1$
    4. $\frac{dy}{dt} = -y - 1$
  5. Consider $\frac{dy}{dt} = -(y-2)^2$. Classify the equilibrium point at $y = 2$.

    1. Stable
    2. Unstable
    3. Semi-stable
    4. Asymptotically stable
  6. For the equation $\frac{dy}{dt} = y^3 - 4y$, find all equilibrium points.

    1. $y = 0$ only
    2. $y = 2$ and $y = -2$ only
    3. $y = 0$, $y = 2$, and $y = -2$
    4. No equilibrium points
  7. If $\frac{dy}{dt} = f(y)$ and $f'(y_e) < 0$ at an equilibrium point $y_e$, what can be said about the stability of $y_e$?

    1. $y_e$ is stable
    2. $y_e$ is unstable
    3. $y_e$ is semi-stable
    4. No conclusion can be made
Click to see Answers
  1. C
  2. B
  3. B
  4. A
  5. C
  6. C
  7. A

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