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Test Questions: Solving Characteristic Equation Case 3 with Euler's Formula

Hey everyone! ๐Ÿ‘‹ Let's conquer characteristic equations, specifically Case 3, using Euler's formula. It sounds intimidating, but I've got a quick study guide and a practice quiz to make it super easy. Get ready to ace those exams! ๐Ÿ’ฏ
๐Ÿงฎ Mathematics

1 Answers

โœ… Best Answer

๐Ÿ“š Quick Study Guide

  • ๐Ÿ”ข When solving a second-order linear homogeneous differential equation with constant coefficients, $ay'' + by' + cy = 0$, Case 3 arises when the characteristic equation $ar^2 + br + c = 0$ has complex conjugate roots, $r = \alpha \pm i\beta$.
  • โž— Euler's formula states that $e^{i\theta} = \cos(\theta) + i\sin(\theta)$. This formula is crucial for expressing complex exponentials in terms of trigonometric functions.
  • โœจ The general solution for Case 3 is given by $y(x) = e^{\alpha x}(c_1 \cos(\beta x) + c_2 \sin(\beta x))$, where $c_1$ and $c_2$ are arbitrary constants determined by initial conditions.
  • ๐Ÿ“ $\alpha$ represents the real part of the complex root, and $\beta$ represents the imaginary part. These values directly influence the amplitude and frequency of the sinusoidal components in the solution.
  • ๐Ÿ“ Remember to apply initial conditions (if provided) to find the specific values of $c_1$ and $c_2$, thus obtaining the particular solution to the differential equation.

Practice Quiz

  1. Question 1: What type of roots does the characteristic equation have in Case 3?
    1. Real and distinct
    2. Real and repeated
    3. Complex conjugate
    4. Rational
  2. Question 2: Given the complex root $r = 2 + 3i$, what are the values of $\alpha$ and $\beta$?
    1. $\alpha = 3$, $\beta = 2$
    2. $\alpha = 2$, $\beta = 3$
    3. $\alpha = -2$, $\beta = 3$
    4. $\alpha = 2$, $\beta = -3$
  3. Question 3: What is the general form of the solution in Case 3?
    1. $y(x) = c_1e^{r_1x} + c_2e^{r_2x}$
    2. $y(x) = (c_1 + c_2x)e^{rx}$
    3. $y(x) = e^{\alpha x}(c_1 \cos(\beta x) + c_2 \sin(\beta x))$
    4. $y(x) = c_1 \cos(\beta x) + c_2 \sin(\beta x)$
  4. Question 4: According to Euler's formula, $e^{i\theta}$ is equal to:
    1. $\sin(\theta) + i\cos(\theta)$
    2. $\cos(\theta) - i\sin(\theta)$
    3. $\cos(\theta) + i\sin(\theta)$
    4. $\sin(\theta) - i\cos(\theta)$
  5. Question 5: If the characteristic equation is $r^2 + 4 = 0$, what are the roots?
    1. $r = \pm 2$
    2. $r = \pm 4$
    3. $r = \pm 2i$
    4. $r = \pm 4i$
  6. Question 6: Given the roots $r = -1 \pm 2i$, what is the general solution?
    1. $y(x) = e^{-x}(c_1 \cos(2x) + c_2 \sin(2x))$
    2. $y(x) = e^{x}(c_1 \cos(2x) + c_2 \sin(2x))$
    3. $y(x) = c_1 \cos(-x) + c_2 \sin(2x)$
    4. $y(x) = e^{-x}(c_1 \cos(x) + c_2 \sin(2x))$
  7. Question 7: In the general solution $y(x) = e^{\alpha x}(c_1 \cos(\beta x) + c_2 \sin(\beta x))$, what do $c_1$ and $c_2$ represent?
    1. The roots of the characteristic equation
    2. Arbitrary constants determined by initial conditions
    3. The real and imaginary parts of the complex root
    4. The coefficients of the differential equation
Click to see Answers
  1. C
  2. B
  3. C
  4. C
  5. C
  6. A
  7. B

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