morris.alison46
morris.alison46 1d ago • 0 views

Differential Equations: Laplace Transform Existence Practice Problems with Solutions

Hey! 👋 Let's test your understanding of when we can actually USE the Laplace Transform. This worksheet will help you practice identifying whether the Laplace Transform exists for different functions. Good luck! 🍀
🧮 Mathematics
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carey.adriana19 Jan 7, 2026

📚 Topic Summary

The Laplace Transform is a powerful tool for solving differential equations, but it only exists for certain functions. A function $f(t)$ has a Laplace Transform if it satisfies two key conditions: First, $f(t)$ must be piecewise continuous on the interval $[0, \infty)$. Second, $f(t)$ must be of exponential order, meaning there exist constants $M$, $K$, and $T$ such that $|f(t)| \le Me^{Kt}$ for all $t > T$. In essence, the function can't grow faster than an exponential function.

Understanding these conditions allows us to quickly determine if a given function is suitable for Laplace Transform techniques. If a function violates either condition, the Laplace Transform does not exist, and alternative methods must be used to solve the differential equation.

🧠 Part A: Vocabulary

Match the following terms with their definitions:

Term Definition
1. Piecewise Continuous A. A function $f(t)$ for which there exist constants $M$, $K$, and $T$ such that $|f(t)| \le Me^{Kt}$ for all $t > T$.
2. Exponential Order B. A transform that converts a function of time to a function of complex frequency.
3. Laplace Transform C. A function that has a finite number of discontinuities and finite limits on any bounded interval.

✍️ Part B: Fill in the Blanks

A function has a Laplace Transform if it is ______ continuous and of ______ order. This means the function does not grow faster than an ______ function.

🤔 Part C: Critical Thinking

Explain, in your own words, why the condition of 'exponential order' is important for the existence of the Laplace Transform. What problems might arise if this condition is not met?

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