lauren131
5d ago • 10 views
Hey there! 👋 Ever wondered if two things are actually related, or if it's just a coincidence? 🤔 The Chi-Square Test for Independence helps us figure that out! Let's dive in!
🧮 Mathematics
1 Answers
✅ Best Answer
darren408
Jan 7, 2026
📚 Quick Study Guide
- 📊 The Chi-Square Test for Independence determines if there is a statistically significant association between two categorical variables.
- 📝 Null Hypothesis ($H_0$): The two variables are independent.
- 🧪 Alternative Hypothesis ($H_1$): The two variables are dependent.
- 🔢 Test Statistic: $\chi^2 = \sum \frac{(O_i - E_i)^2}{E_i}$, where $O_i$ is the observed frequency and $E_i$ is the expected frequency.
- 📈 Degrees of Freedom: $df = (r - 1)(c - 1)$, where $r$ is the number of rows and $c$ is the number of columns in the contingency table.
- 🌍 Significance Level: Commonly set at $\alpha = 0.05$.
- 💡 Decision Rule: If the p-value is less than $\alpha$, reject the null hypothesis.
Practice Quiz
-
Which of the following is the primary purpose of the Chi-Square Test for Independence?
- To determine the mean of a population.
- To assess the correlation between two continuous variables.
- To determine if there is an association between two categorical variables.
- To compare the variances of two populations.
-
What is the null hypothesis ($H_0$) in a Chi-Square Test for Independence?
- The two variables are dependent.
- The two variables are independent.
- There is a significant difference between the means of the two variables.
- The variance of the two variables is equal.
-
What does a significant result in a Chi-Square Test for Independence indicate?
- The two variables are independent.
- The two variables are strongly correlated.
- There is evidence to suggest an association between the two variables.
- The sample size is too small.
-
How is the expected frequency ($E_i$) calculated in a Chi-Square Test?
- $E_i = \frac{\text{Row Total} + \text{Column Total}}{\text{Grand Total}}$
- $E_i = \frac{\text{Row Total} \times \text{Column Total}}{\text{Grand Total}}$
- $E_i = \frac{\text{Grand Total}}{\text{Row Total} \times \text{Column Total}}$
- $E_i = \text{Row Total} \times \text{Column Total} \times \text{Grand Total}$
-
What are the degrees of freedom ($df$) for a Chi-Square Test in a contingency table with 3 rows and 4 columns?
- 12
- 7
- 6
- 9
-
What is the typical significance level ($\alpha$) used in a Chi-Square Test?
- 0.10
- 0.01
- 0.05
- 0.20
-
In a Chi-Square Test, if the p-value is 0.03 and the significance level is 0.05, what is the correct decision?
- Fail to reject the null hypothesis.
- Reject the alternative hypothesis.
- Reject the null hypothesis.
- Increase the sample size.
Click to see Answers
- C
- B
- C
- B
- C
- C
- C
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