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Coefficient of Performance (COP) Formula: Explained with Examples

Hey everyone! 👋 Ever wondered how efficient your fridge or AC really is? 🤔 It's all about the Coefficient of Performance (COP)! Let's break down the formula with some easy examples and then test your knowledge with a quick quiz!
⚛️ Physics

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📚 Quick Study Guide

  • 🧊 The Coefficient of Performance (COP) measures the efficiency of a heat pump or refrigeration system.
  • 🌡️ COP is defined as the ratio of useful heating or cooling provided to the work required.
  • 🔢 For heating: $COP_{heating} = \frac{Q_{hot}}{W_{in}}$, where $Q_{hot}$ is the heat delivered to the hot reservoir and $W_{in}$ is the work input.
  • ❄️ For cooling: $COP_{cooling} = \frac{Q_{cold}}{W_{in}}$, where $Q_{cold}$ is the heat removed from the cold reservoir and $W_{in}$ is the work input.
  • 💡 A higher COP indicates greater efficiency.

Practice Quiz

  1. Which of the following best describes the Coefficient of Performance (COP)?
    1. (A) The amount of work done by a system.
    2. (B) The ratio of useful heating or cooling to the work required.
    3. (C) The temperature difference between two reservoirs.
    4. (D) The rate of heat transfer in a system.
  2. What does a higher COP value indicate?
    1. (A) Lower efficiency.
    2. (B) Greater efficiency.
    3. (C) No change in efficiency.
    4. (D) Higher work input required.
  3. For a heating system, the COP is calculated as:
    1. (A) $\frac{W_{in}}{Q_{hot}}$
    2. (B) $\frac{Q_{cold}}{W_{in}}$
    3. (C) $\frac{Q_{hot}}{W_{in}}$
    4. (D) $\frac{Q_{hot}}{Q_{cold}}$
  4. A refrigerator removes 120 J of heat from the cold reservoir with a work input of 40 J. What is its COP?
    1. (A) 0.33
    2. (B) 3
    3. (C) 4800
    4. (D) 160
  5. Which of the following factors can affect the COP of a heat pump?
    1. (A) Temperature difference between the reservoirs.
    2. (B) Type of refrigerant used.
    3. (C) System design.
    4. (D) All of the above.
  6. For a cooling system, $Q_{cold}$ represents:
    1. (A) Heat delivered to the hot reservoir.
    2. (B) Work input.
    3. (C) Heat removed from the cold reservoir.
    4. (D) Total energy of the system.
  7. A heat pump has a COP of 3.5 and delivers 700 J of heat. How much work input is required?
    1. (A) 2450 J
    2. (B) 200 J
    3. (C) 0.005 J
    4. (D) 703.5 J
Click to see Answers
  1. B
  2. B
  3. C
  4. B
  5. D
  6. C
  7. B

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