Power Factor Correction Quiz with Answers: Test Your Knowledge

📚 Quick Study Guide

• ⚡ Power Factor (PF): The ratio of real power (kW) to apparent power (kVA). It indicates how effectively electrical power is being used. $PF = \frac{kW}{kVA}$
• 📉 Low Power Factor: Can result in increased energy costs, overloaded equipment, and voltage drops.
• 💡 Power Factor Correction: The process of improving the power factor by reducing the reactive power component.
• ⚙️ Capacitors: Commonly used for power factor correction. They supply reactive power, offsetting the inductive reactive power drawn by loads.
• 📐 Leading and Lagging PF: Inductive loads (motors, transformers) cause lagging PF. Capacitive loads cause leading PF.
• ➕ Benefits of PFC: Reduced energy bills, improved voltage regulation, increased system capacity, and reduced losses.
• ➗ Calculating Capacitor Size: $Q_c = P(\tan(\phi_1) - \tan(\phi_2))$, where $Q_c$ is the reactive power of the capacitor, $P$ is the real power, $\phi_1$ is the initial phase angle, and $\phi_2$ is the desired phase angle.

🧪 Practice Quiz

1. What is Power Factor (PF) defined as?
   1. A. The ratio of apparent power to real power.
   2. B. The ratio of real power to apparent power.
   3. C. The sum of real and reactive power.
   4. D. The difference between real and reactive power.
2. Which of the following is a consequence of low power factor?
   1. A. Reduced energy costs.
   2. B. Improved voltage regulation.
   3. C. Increased energy costs.
   4. D. Decreased system capacity.
3. What device is commonly used for power factor correction?
   1. A. Inductors
   2. B. Resistors
   3. C. Capacitors
   4. D. Transformers
4. What type of power factor do inductive loads typically cause?
   1. A. Leading power factor
   2. B. Lagging power factor
   3. C. Unity power factor
   4. D. Zero power factor
5. Which of the following is a benefit of Power Factor Correction (PFC)?
   1. A. Increased energy bills
   2. B. Reduced system capacity
   3. C. Improved voltage regulation
   4. D. Increased line losses
6. If $P = 100kW$, initial $\phi_1 = 60°$, and desired $\phi_2 = 30°$, what is the reactive power ($Q_c$) of the capacitor needed for correction, using the formula $Q_c = P(\tan(\phi_1) - \tan(\phi_2))$?
   1. A. 26.8 kVAR
   2. B. 57.7 kVAR
   3. C. 73.2 kVAR
   4. D. 126.8 kVAR
7. What does a power factor close to 1 indicate?
   1. A. High reactive power, low real power.
   2. B. Low reactive power, high real power.
   3. C. Equal reactive and real power.
   4. D. No real power consumption.