1 Answers
📚 Understanding the Combined Gas Law
The Combined Gas Law is a powerful tool in chemistry that allows us to analyze how the volume of a gas changes when temperature and pressure also change. It's essentially a combination of Boyle's Law, Charles's Law, and Gay-Lussac's Law.
📜 History and Background
The Combined Gas Law wasn't discovered by a single scientist but evolved from the individual observations of Boyle, Charles, and Gay-Lussac. They each studied the relationship between two of the variables (pressure, volume, and temperature) while keeping the third constant. Combining their findings led to the Combined Gas Law.
⚗️ Key Principles
The Combined Gas Law is expressed mathematically as:
$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$
Where:
- 📊 $P_1$ is the initial pressure.
- 📦 $V_1$ is the initial volume.
- 🌡️ $T_1$ is the initial absolute temperature (in Kelvin).
- 🧭 $P_2$ is the final pressure.
- 🧱 $V_2$ is the final volume.
- 🔥 $T_2$ is the final absolute temperature (in Kelvin).
Important Notes:
- 🌡️ Temperature must always be in Kelvin. To convert from Celsius to Kelvin, use the formula: $K = °C + 273.15$.
- 📏 Pressure and volume units must be consistent on both sides of the equation (e.g., both pressures in atm, both volumes in liters).
🧪 How to Calculate Volume Changes
To calculate volume changes, rearrange the Combined Gas Law to solve for $V_2$:
$V_2 = \frac{P_1V_1T_2}{P_2T_1}$
Steps:
- 📝 Identify: Identify the knowns ($P_1, V_1, T_1, P_2, T_2$) from the problem statement.
- 🔄 Convert: Convert temperatures to Kelvin and ensure consistent pressure and volume units.
- Plug: Plug the values into the rearranged formula.
- 🧮 Solve: Solve for $V_2$.
🌍 Real-world Examples
Example 1: Inflating a Balloon
A balloon has a volume of 1.0 L at 25°C and 1.0 atm. If the temperature is increased to 50°C and the pressure is decreased to 0.5 atm, what is the new volume of the balloon?
Solution:
- 🏷️ $P_1 = 1.0 \text{ atm}$
- 🎈 $V_1 = 1.0 \text{ L}$
- 🌡️ $T_1 = 25 + 273.15 = 298.15 \text{ K}$
- 📉 $P_2 = 0.5 \text{ atm}$
- 🔥 $T_2 = 50 + 273.15 = 323.15 \text{ K}$
Using the formula:
$V_2 = \frac{(1.0 \text{ atm})(1.0 \text{ L})(323.15 \text{ K})}{(0.5 \text{ atm})(298.15 \text{ K})} = 2.16 \text{ L}$
Example 2: Syringe Volume
A gas in a syringe has a volume of 50.0 mL at standard temperature and pressure (STP: 0°C and 1 atm). If the pressure is increased to 2.0 atm and the temperature is increased to 100°C, what is the new volume?
Solution:
- 📌 $P_1 = 1.0 \text{ atm}$
- 💉 $V_1 = 50.0 \text{ mL}$
- 🧊 $T_1 = 0 + 273.15 = 273.15 \text{ K}$
- 📈 $P_2 = 2.0 \text{ atm}$
- ♨️ $T_2 = 100 + 273.15 = 373.15 \text{ K}$
Using the formula:
$V_2 = \frac{(1.0 \text{ atm})(50.0 \text{ mL})(373.15 \text{ K})}{(2.0 \text{ atm})(273.15 \text{ K})} = 34.1 \text{ mL}$
📝 Conclusion
The Combined Gas Law is essential for predicting how volume changes with pressure and temperature. By understanding the formula and practicing with examples, you can confidently solve a wide range of gas-related problems! 🎉
🤔 Practice Quiz
Test your understanding with these practice problems:
- 🎈 A gas occupies 10.0 L at STP. What volume will it occupy at 300 K and 1.5 atm?
- 🔥 A container of gas has a volume of 5.0 L at 20°C and 2.0 atm. If the pressure is changed to 1.0 atm and the temperature is increased to 40°C, what is the new volume?
- 🧊 A gas occupies a volume of 25.0 mL at 25°C and 760 torr. What volume will it occupy at 50°C and 800 torr?
Answers:
- $V_2 = 7.39 \text{ L}$
- $V_2 = 10.51 \text{ L}$
- $V_2 = 26.46 \text{ mL}$
Join the discussion
Please log in to post your answer.
Log InEarn 2 Points for answering. If your answer is selected as the best, you'll get +20 Points! 🚀