1 Answers
📚 Quick Study Guide
- 🧪 Solubility Rules: These are general guidelines that tell you whether a compound will dissolve in water. Memorize key rules (e.g., all nitrates are soluble).
- ⚖️ Solubility Product Constant ($K_{sp}$): This value represents the equilibrium constant for the dissolution of a solid in water. A smaller $K_{sp}$ indicates lower solubility. The equation for $K_{sp}$ for a generic salt $A_xB_y$ is $K_{sp} = [A^{+y}]^x[B^{-x}]^y$.
- 🤔 Ion Product (Q): Q is calculated the same way as $K_{sp}$, but using initial concentrations instead of equilibrium concentrations.
- 💡 Comparing Q and $K_{sp}$:
- If $Q < K_{sp}$, the solution is unsaturated and more solid can dissolve. No precipitation occurs.
- If $Q = K_{sp}$, the solution is saturated and the system is at equilibrium.
- If $Q > K_{sp}$, the solution is supersaturated and precipitation will occur until $Q = K_{sp}$.
- 📝 Predicting Precipitation: Calculate Q based on the initial ion concentrations. Compare Q to the $K_{sp}$ value provided.
Practice Quiz
-
Which of the following compounds is generally considered insoluble in water according to solubility rules?
- A. $NaNO_3$
- B. $KCl$
- C. $AgCl$
- D. $Li_2SO_4$
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The solubility product constant ($K_{sp}$) for $AgCl$ is $1.8 \times 10^{-10}$. What is the molar solubility of $AgCl$ in pure water?
- A. $1.8 \times 10^{-10}$ M
- B. $9.0 \times 10^{-5}$ M
- C. $1.34 \times 10^{-5}$ M
- D. $3.6 \times 10^{-20}$ M
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A solution contains $[Ag^+] = 2.0 \times 10^{-5}$ M and $[Cl^-] = 3.0 \times 10^{-6}$ M. Will a precipitate of $AgCl$ form? ($K_{sp}$ of $AgCl = 1.8 \times 10^{-10}$)
- A. Yes, because Q > $K_{sp}$
- B. No, because Q < $K_{sp}$
- C. Yes, because Q < $K_{sp}$
- D. No, because Q > $K_{sp}$
-
What is the correct $K_{sp}$ expression for the dissolution of $PbCl_2(s)$ in water?
- A. $K_{sp} = [Pb^{2+}][Cl^-]$
- B. $K_{sp} = [Pb^{2+}][2Cl^-]$
- C. $K_{sp} = [Pb^{2+}][Cl^-]^2$
- D. $K_{sp} = [Pb^{2+}]^2[Cl^-]^2$
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If a solution contains $0.01$ M $Pb^{2+}$ and $0.01$ M $Cl^-$, will $PbCl_2$ precipitate? The $K_{sp}$ of $PbCl_2$ is $1.6 \times 10^{-5}$.
- A. Yes, because Q > $K_{sp}$
- B. No, because Q < $K_{sp}$
- C. The solution is at equilibrium.
- D. More information is needed.
-
Which of the following actions will NOT affect the solubility of $AgCl$?
- A. Adding NaCl
- B. Adding $AgNO_3$
- C. Adding $NH_3$
- D. Adding $KNO_3$
-
The $K_{sp}$ of $CaF_2$ is $3.9 \times 10^{-11}$. What is the concentration of $Ca^{2+}$ in a saturated solution of $CaF_2$?
- A. $3.9 \times 10^{-11}$ M
- B. $1.95 \times 10^{-11}$ M
- C. $2.2 \times 10^{-4}$ M
- D. $3.4 \times 10^{-4}$ M
Click to see Answers
- C
- C
- A
- C
- A
- D
- C
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