1 Answers
📚 What is Vapor Pressure Correction?
Vapor pressure correction is the adjustment made to experimental measurements of gas volumes collected over a liquid (usually water) to account for the presence of water vapor in the collected gas. When a gas is collected over water, some of the water evaporates and mixes with the gas. This water vapor contributes to the total pressure of the collected gas. To determine the true pressure of the gas itself, we need to subtract the vapor pressure of water at the given temperature from the total pressure.
🕰️ A Brief History
The concept of vapor pressure and its correction became important as scientists began to precisely measure and analyze gases in the 18th and 19th centuries. Early chemists like John Dalton recognized that water vapor significantly affected gas measurements, leading to the development of correction methods. Dalton's Law of Partial Pressures provided a fundamental basis for understanding and correcting for vapor pressure.
🔑 Key Principles
- ⚖️ Dalton's Law of Partial Pressures: The total pressure of a mixture of gases is equal to the sum of the partial pressures of each individual gas. Mathematically: $P_{total} = P_{gas} + P_{H_2O}$
- 🌡️ Temperature Dependence: Vapor pressure of water increases with temperature. Higher temperature means more water molecules have enough energy to escape into the gas phase.
- 💧 Vapor Pressure Tables: Vapor pressure values for water at different temperatures are readily available in reference tables. These values are experimentally determined and crucial for accurate corrections.
- 📐 Correction Formula: The corrected pressure of the dry gas ($P_{gas}$) is obtained by subtracting the vapor pressure of water ($P_{H_2O}$) at the experimental temperature from the total pressure ($P_{total}$): $P_{gas} = P_{total} - P_{H_2O}$
🧪 Real-world Examples
Example 1: Collecting Oxygen Gas
Oxygen gas is collected over water at 25°C. The total pressure of the system is measured to be 768 torr. What is the pressure of the dry oxygen gas?
Solution:
- 🌡️ Find the vapor pressure of water at 25°C from a reference table. $P_{H_2O}$ = 23.8 torr
- ➗ Use the correction formula: $P_{O_2} = P_{total} - P_{H_2O}$
- 🔢 Substitute the values: $P_{O_2} = 768 torr - 23.8 torr = 744.2 torr$
Therefore, the pressure of the dry oxygen gas is 744.2 torr.
Example 2: Determining Molar Volume
Hydrogen gas is collected over water. The volume of gas collected is 500 mL at 20°C and a total pressure of 750 mmHg. Calculate the number of moles of hydrogen gas collected.
Solution:
- 💧 Find the vapor pressure of water at 20°C from a reference table. $P_{H_2O}$ = 17.5 mmHg
- ➖ Correct the total pressure to find the pressure of dry hydrogen gas: $P_{H_2} = P_{total} - P_{H_2O} = 750 mmHg - 17.5 mmHg = 732.5 mmHg$
- ↔️ Convert pressure to atm: $P_{H_2} = 732.5 mmHg \times \frac{1 atm}{760 mmHg} = 0.964 atm$
- 📏 Convert volume to liters: $V = 500 mL = 0.5 L$
- 🔥 Use the ideal gas law ($PV=nRT$) to solve for n (number of moles): $n = \frac{PV}{RT}$
- ⚙️ Substitute the values: $n = \frac{(0.964 atm)(0.5 L)}{(0.0821 L \cdot atm \cdot mol^{-1} \cdot K^{-1})(293 K)} = 0.020 moles$
Therefore, 0.020 moles of hydrogen gas were collected.
✏️ Practice Quiz
| Question | Answer |
|---|---|
| A gas is collected over water at 30°C. The total pressure is 775 torr. What is the partial pressure of the dry gas? (Vapor pressure of water at 30°C is 31.8 torr) | 743.2 torr |
| If the vapor pressure of water at 22°C is 19.8 torr and a gas is collected over water at the same temperature with a total pressure of 762 torr, what is the pressure of the dry gas? | 742.2 torr |
| A student collects nitrogen gas over water at 27°C. The atmospheric pressure is 756 mmHg. What is the pressure of the dry nitrogen gas? (Vapor pressure of water at 27°C is 26.7 mmHg) | 729.3 mmHg |
💡 Conclusion
Vapor pressure correction is essential for accurate gas measurements when collecting gases over liquids. By understanding Dalton's Law and using vapor pressure tables, you can confidently correct for the presence of water vapor and obtain reliable results in your experiments. Keep practicing, and you'll master this technique in no time! 🎉
Join the discussion
Please log in to post your answer.
Log InEarn 2 Points for answering. If your answer is selected as the best, you'll get +20 Points! 🚀