1 Answers
📚 Quick Study Guide
- 🧊 Freezing Point Depression: A colligative property where the freezing point of a solvent is lowered when a solute is added.
- 🌡️ Formula: $\Delta T_f = K_f \cdot m \cdot i$, where:
- $\Delta T_f$ is the freezing point depression.
- $K_f$ is the cryoscopic constant of the solvent.
- $m$ is the molality of the solution (moles of solute per kg of solvent).
- $i$ is the van't Hoff factor (number of particles the solute dissociates into).
- ⚖️ Molality (m): $m = \frac{\text{moles of solute}}{\text{kg of solvent}}$
- ➕ Van't Hoff factor (i):
- For non-electrolytes (like sugar), $i = 1$.
- For electrolytes (like NaCl, which dissociates into Na+ and Cl-), $i$ is approximately the number of ions formed.
- 📝 Calculating Freezing Point: Freezing Point of Solution = Freezing Point of Pure Solvent - $\Delta T_f$
Practice Quiz
-
What is the freezing point depression ($\Delta T_f$) when 0.1 moles of glucose are dissolved in 100 g of water? ( $K_f$ for water = 1.86 °C kg/mol, i = 1)
- 0.186 °C
- 1.86 °C
- 18.6 °C
- 0.0186 °C
-
What is the molality of a solution containing 20 g of NaCl (molar mass = 58.44 g/mol) in 500 g of water?
- 0.068 m
- 0.68 m
- 6.8 m
- 0.0068 m
-
If the freezing point of pure water is 0 °C, what is the freezing point of a solution containing 0.2 moles of NaCl in 200 g of water? ($K_f$ for water = 1.86 °C kg/mol, i = 2)
- -3.72 °C
- 3.72 °C
- -1.86 °C
- 1.86 °C
-
Which of the following solutions will have the lowest freezing point? (Assume i=1 for all solutes)
- 1 m Glucose
- 0.5 m Sucrose
- 0.2 m NaCl
- 0.1 m $CaCl_2$
-
What is the van't Hoff factor for $MgCl_2$ when it completely dissociates in water?
- 1
- 2
- 3
- 4
-
A solution containing which of the following solutes will cause the greatest freezing point depression in water, assuming equal molal concentrations?
- Glucose
- Sucrose
- NaCl
- $AlCl_3$
-
What mass of ethylene glycol (molar mass = 62.07 g/mol) must be added to 1.0 kg of water to produce a solution that freezes at -5.0 °C? ($K_f$ for water = 1.86 °C kg/mol, i = 1)
- 167 g
- 1.67 g
- 2.68 g
- 267 g
Click to see Answers
- A
- B
- A
- A
- C
- D
- A
Join the discussion
Please log in to post your answer.
Log InEarn 2 Points for answering. If your answer is selected as the best, you'll get +20 Points! 🚀