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📚 Quick Study Guide
- 🌡️ Charles's Law describes the relationship between the volume and temperature of a gas at constant pressure.
- ➗ The formula for Charles's Law is: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$, where $V$ is volume and $T$ is temperature (in Kelvin).
- ♨️ As temperature increases, volume increases proportionally (and vice-versa).
- 📝 Temperature must ALWAYS be in Kelvin. To convert from Celsius to Kelvin: $K = °C + 273.15$
- 🎈 Examples include hot air balloons, car tires, and baking.
Practice Quiz
-
A balloon has a volume of 3.0 L at 27°C. If the temperature is increased to 227°C, what is the new volume of the balloon, assuming the pressure remains constant?
- 1.0 L
- 5.0 L
- 3.0 L
- 7.0 L
-
Which of the following is an everyday example of Charles's Law in action?
- A refrigerator cooling food
- A pressure cooker increasing cooking speed
- A hot air balloon rising
- A syringe drawing liquid
-
A gas occupies 10.0 L at standard temperature (273.15 K). What volume will it occupy if the temperature is doubled (at constant pressure)?
- 5.0 L
- 10.0 L
- 20.0 L
- 40.0 L
-
In the context of Charles's Law, what must remain constant?
- Temperature
- Volume
- Pressure
- Moles of gas
-
Why is it important to convert Celsius to Kelvin when using Charles's Law?
- Kelvin is a smaller unit, providing more accurate results
- Celsius can have negative values, which would cause errors in the calculation
- The formula only works with Kelvin
- Celsius is an outdated unit of measurement
-
A car tire has a volume of 30 L at 20°C. After driving, the temperature increases to 40°C. What is the new volume of the tire, assuming constant pressure?
- 28 L
- 32 L
- 60 L
- 30 L
-
Which industrial application directly utilizes Charles's Law?
- Manufacturing of liquid nitrogen
- Operation of refrigeration systems
- Design of airbags in cars
- Inflation of weather balloons
Click to see Answers
- B
- C
- C
- C
- B
- B
- D
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