1 Answers
📚 Quick Study Guide
- 🌡️ Boiling point elevation is a colligative property, meaning it depends on the number of solute particles, not their identity.
- ⚗️ The formula for boiling point elevation is: $\Delta T_b = iK_bm$, where $\Delta T_b$ is the boiling point elevation, $i$ is the van't Hoff factor, $K_b$ is the ebullioscopic constant, and $m$ is the molality of the solution.
- 💧 Molality ($m$) is defined as moles of solute per kilogram of solvent.
- 🧊 The van't Hoff factor ($i$) represents the number of ions a solute dissociates into when dissolved in a solution. For example, NaCl has $i=2$ because it dissociates into Na$^+$ and Cl$^-$ ions.
- 🔥 Real-world applications include antifreeze in car radiators (ethylene glycol elevates the boiling point and depresses the freezing point) and cooking (adding salt to water increases the boiling point slightly).
- 💡 Remember to convert grams to moles and grams to kilograms when calculating molality.
🧪 Practice Quiz
-
What type of property is boiling point elevation?
- Intensive property
- Additive property
- Colligative property
- Extensive property
-
What does the van't Hoff factor represent?
- The molar mass of the solute
- The number of ions a solute dissociates into
- The density of the solution
- The volume of the solvent
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If $K_b$ for water is 0.512 °C kg/mol, what is the boiling point elevation of a solution containing 2 moles of solute in 1 kg of water, assuming $i = 1$?
- 0.256 °C
- 0.512 °C
- 1.024 °C
- 2.048 °C
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Which of the following is an example of boiling point elevation in everyday life?
- Melting ice
- Adding salt to a roadway in winter
- Using antifreeze in a car radiator
- Freezing water
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What is the molality of a solution containing 4 grams of NaOH (molar mass = 40 g/mol) in 500 g of water?
- 0.1 m
- 0.2 m
- 0.008 m
- 0.02 m
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A solution contains 10 grams of glucose (molar mass = 180 g/mol) in 200 g of water. Calculate the molality of the solution.
- 0.278 m
- 0.556 m
- 0.056 m
- 1.11 m
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What is the boiling point elevation if 0.5 moles of NaCl are dissolved in 1 kg of water? (Assume $K_b$ = 0.512 °C kg/mol for water)
- 0.256 °C
- 0.512 °C
- 1.024 °C
- 0.768 °C
Click to see Answers
- C
- B
- C
- C
- B
- A
- B
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