anne.andrews
anne.andrews 3d ago • 10 views

Quadratic equations examples

Hey there! 👋 Quadratic equations can seem tricky, but with the right approach, they become much easier to handle. This guide will give you a quick rundown, and then you can test your knowledge with a quiz! Let's get started! 🤓
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marshall.daniel8 Dec 26, 2025

📚 Quick Study Guide

  • 🔍 Standard Form: A quadratic equation is typically written as $ax^2 + bx + c = 0$, where $a$, $b$, and $c$ are constants, and $a \neq 0$.
  • Solving by Factoring: Factor the quadratic expression into two binomials, then set each binomial equal to zero and solve for $x$. For example, $x^2 + 5x + 6 = (x+2)(x+3)=0$, so $x=-2$ or $x=-3$.
  • 💡 Quadratic Formula: When factoring is difficult or impossible, use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$.
  • 📈 Discriminant: The discriminant, $b^2 - 4ac$, determines the nature of the roots:
    • If $b^2 - 4ac > 0$, there are two distinct real roots.
    • If $b^2 - 4ac = 0$, there is one real root (a repeated root).
    • If $b^2 - 4ac < 0$, there are two complex roots.
  • 📝 Completing the Square: A method to rewrite the quadratic equation into the form $(x + p)^2 = q$, making it easier to solve for $x$.

🧪 Practice Quiz

  1. What are the solutions to the quadratic equation $x^2 - 5x + 6 = 0$?
    1. x = 2, x = 3
    2. x = -2, x = -3
    3. x = 1, x = 6
    4. x = -1, x = -6
  2. Solve for $x$: $2x^2 + 7x + 3 = 0$
    1. x = -3, x = -1/2
    2. x = 3, x = 1/2
    3. x = -3, x = 1/2
    4. x = 3, x = -1/2
  3. What is the discriminant of the quadratic equation $3x^2 - 4x + 2 = 0$?
    1. -8
    2. 8
    3. 40
    4. -40
  4. How many real solutions does the equation $x^2 + 6x + 9 = 0$ have?
    1. 0
    2. 1
    3. 2
    4. 3
  5. Find the roots of the equation $x^2 - 9 = 0$.
    1. x = 3, x = -3
    2. x = 9, x = -9
    3. x = 3
    4. x = -3
  6. Solve $x^2 + 2x - 8 = 0$ by factoring.
    1. x = 2, x = -4
    2. x = -2, x = 4
    3. x = 1, x = -8
    4. x = -1, x = 8
  7. Using the quadratic formula, find the solutions to $x^2 + 4x + 1 = 0$.
    1. x = -2 ± \sqrt{3}
    2. x = 2 ± \sqrt{3}
    3. x = -4 ± \sqrt{5}
    4. x = 4 ± \sqrt{5}
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