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📚 Quick Study Guide
- 🔑 The `get(int index)` method retrieves the element at the specified position in an `ArrayList`.
- 🔢 Indexing in Java `ArrayLists` starts at 0. So, the first element is at index 0, the second at index 1, and so on.
- 🚨 If you try to access an index that is out of bounds (i.e., less than 0 or greater than or equal to the size of the `ArrayList`), an `IndexOutOfBoundsException` will be thrown.
- 📏 The valid index range for an `ArrayList` of size `n` is from 0 to `n-1`.
- ⏱️ The `get()` method provides constant time complexity, O(1), for accessing elements.
- 💡 Always check the size of the `ArrayList` before calling `get()` to avoid exceptions.
🧪 Practice Quiz
-
What is the index of the first element in an `ArrayList`?
- -1
- 0
- 1
- The size of the `ArrayList`
-
What happens if you try to access an index that is out of bounds in an `ArrayList` using the `get()` method?
- It returns `null`.
- It returns a default value.
- It throws an `IndexOutOfBoundsException`.
- It resizes the `ArrayList`.
-
Given an `ArrayList` named `myList` with 5 elements, what is the valid range of indices you can access using the `get()` method?
- 0 to 5
- 1 to 5
- 0 to 4
- 1 to 4
-
What is the time complexity of the `get()` method in an `ArrayList`?
- O(n)
- O(log n)
- O(1)
- O(n^2)
-
How can you prevent an `IndexOutOfBoundsException` when using the `get()` method?
- Always access the last element.
- Always access the first element.
- Check the size of the `ArrayList` before accessing an element.
- Use a try-catch block without checking the size.
-
Consider an `ArrayList` called `numbers` containing the integers [10, 20, 30, 40, 50]. What will `numbers.get(2)` return?
- 10
- 20
- 30
- 40
-
If an `ArrayList` is empty, what happens when you call `get(0)`?
- Returns 0.
- Returns null.
- Throws an `IndexOutOfBoundsException`.
- Creates a new element at index 0.
Click to see Answers
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