๐ Topic Summary
In Java, if statements are fundamental for decision-making in your code. They allow you to execute different blocks of code based on whether a specified condition is true or false. The basic structure involves the if keyword, followed by a condition in parentheses, and a block of code enclosed in curly braces. You can also use else if to check multiple conditions and else to execute a block of code when none of the conditions are true.
These statements are critical for creating dynamic and responsive programs that react differently based on user input, data values, or other variables. Mastering if statements is crucial for any AP Computer Science A student.
๐ง Part A: Vocabulary
Match the term with its definition:
| Term |
Definition |
| 1. Condition |
A. A statement that is executed if the condition is false. |
| 2. If Statement |
B. A boolean expression that is evaluated to true or false. |
| 3. Else Statement |
C. A block of code that is executed if a certain condition is true. |
| 4. Else If Statement |
D. A statement that checks a new condition if the previous condition is false. |
| 5. Boolean |
E. A data type that has two possible values: true or false. |
(Answers: 1-B, 2-C, 3-A, 4-D, 5-E)
๐ Part B: Fill in the Blanks
Complete the following paragraph using the words: if, else, condition, true, false.
An _______ statement is used to execute a block of code when a _______ is _______. If the _______ is _______, the _______ block is executed. Otherwise, the _______ block can be executed.
(Answers: if, condition, true, condition, false, if, else)
๐ค Part C: Critical Thinking
Explain a real-world scenario where an if statement would be useful in a Java program. Provide a code snippet to illustrate your explanation.
(Example Answer: An if statement could be used to control access to a restricted area based on a user's age. If the user is 18 or older, they are granted access; otherwise, they are denied. Code snippet: int age = input.nextInt(); if (age >= 18) { System.out.println("Access granted."); } else { System.out.println("Access denied."); })