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University Linear Algebra Subspace Proof Worksheets & Solutions

Hey there! 👋 Struggling with subspace proofs in linear algebra? Don't worry, you're not alone! This worksheet will help you solidify your understanding with definitions, fill-in-the-blanks, and a critical thinking question. Let's get started! 🤓
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📚 Topic Summary

In linear algebra, a subspace is a subset of a vector space that is itself a vector space under the same operations defined for the larger vector space. To prove a subset $W$ is a subspace of a vector space $V$, you must show that $W$ is non-empty, closed under addition (i.e., if $\mathbf{u}, \mathbf{v} \in W$, then $\mathbf{u} + \mathbf{v} \in W$), and closed under scalar multiplication (i.e., if $\mathbf{u} \in W$ and $c$ is a scalar, then $c\mathbf{u} \in W$). These three conditions guarantee that $W$ satisfies all the vector space axioms. Proving these properties is the core skill tested by subspace proof worksheets.

Essentially, subspace proofs are about verifying that a smaller space behaves like the larger vector space it lives within. It's a key concept for understanding linear transformations and other advanced topics.

🧠 Part A: Vocabulary

Match the term with its correct definition:

Term Definition
1. Vector Space A. A subset of a vector space that is itself a vector space.
2. Subspace B. A real number that scales a vector.
3. Closure under Addition C. A set with operations of addition and scalar multiplication that satisfy certain axioms.
4. Closure under Scalar Multiplication D. If $\mathbf{u}$ is in W, then $c\mathbf{u}$ is also in W.
5. Scalar E. If $\mathbf{u}$ and $\mathbf{v}$ are in W, then $\mathbf{u} + \mathbf{v}$ is also in W.

✏️ Part B: Fill in the Blanks

To prove that a subset $W$ of a vector space $V$ is a __________, you must show three things: first, that $W$ is __________. Second, that $W$ is closed under __________, meaning that if $\mathbf{u}$ and $\mathbf{v}$ are in $W$, then their __________ is also in $W$. Third, that $W$ is closed under __________, meaning that if $\mathbf{u}$ is in $W$ and $c$ is a scalar, then $c\mathbf{u}$ is also in $W$.

🤔 Part C: Critical Thinking

Let $V = \mathbb{R}^2$. Let $W = \{(x, y) \in \mathbb{R}^2 : x = y^2\}$. Is $W$ a subspace of $V$? Justify your answer with a proof or a counterexample.

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