1 Answers
๐ Sum vs. Direct Sum: Unveiling the Differences
In linear algebra, both the sum and direct sum are ways of combining subspaces to create larger vector spaces. However, they differ in a crucial aspect: the uniqueness of representation. Let's break it down:
โ Definition of Sum of Subspaces
The sum of subspaces $U$ and $W$ (denoted $U + W$) is the set of all possible sums of vectors from $U$ and $W$. Mathematically:
$U + W = \{u + w \mid u \in U, w \in W\}$
- โ Elements: The sum $U + W$ consists of all vectors that can be written as the sum of a vector from $U$ and a vector from $W$.
- ๐ Representation: The representation of a vector in $U + W$ as $u + w$ is not necessarily unique.
โ Definition of Direct Sum of Subspaces
The direct sum of subspaces $U$ and $W$ (denoted $U \oplus W$) is the sum $U + W$ with the additional requirement that the representation of any vector in $U + W$ as $u + w$ is unique. Equivalently, $U \cap W = \{0\}$. Mathematically,
$U \oplus W = \{u + w \mid u \in U, w \in W, \text{ and } U \cap W = \{0\}\}$
- โ Elements: The direct sum $U \oplus W$ also consists of vectors that can be written as the sum of a vector from $U$ and a vector from $W$.
- ๐ Representation: The representation of a vector in $U \oplus W$ as $u + w$ is unique. This is the defining characteristic!
- ๐ซ Intersection: $U \cap W = \{0\}$. The only vector that $U$ and $W$ share is the zero vector.
๐ Sum vs. Direct Sum: A Comparison Table
| Feature | Sum of Subspaces ($U + W$) | Direct Sum of Subspaces ($U \oplus W$) |
|---|---|---|
| Definition | Set of all vectors $u + w$, where $u \in U$ and $w \in W$. | Set of all vectors $u + w$, where $u \in U$, $w \in W$, and $U \cap W = \{0\}$. |
| Representation | Representation $u + w$ is not necessarily unique. | Representation $u + w$ is unique. |
| Intersection | $U \cap W$ can be any subspace. | $U \cap W = \{0\}$. |
๐ Key Takeaways
- โ Uniqueness: The key difference lies in the uniqueness of representing vectors as a sum of vectors from the subspaces.
- ๐ฏ Intersection: If the intersection of the subspaces is only the zero vector, and the sum spans the entire space, then it's a direct sum.
- ๐ก Implication: If you can express any vector in the combined space uniquely as a sum of vectors from the subspaces, you're dealing with a direct sum.
Join the discussion
Please log in to post your answer.
Log InEarn 2 Points for answering. If your answer is selected as the best, you'll get +20 Points! ๐