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josephmarks2000 4d ago โ€ข 0 views

Solving Pre-Calculus Problems Using Sum and Difference Identities

Hey everyone! ๐Ÿ‘‹ Math can be tough, especially when you're staring down trig identities. Sum and difference identities felt like a total mystery to me at first. But once I understood how they worked, solving those pre-calculus problems got SO much easier! Let's break it down and conquer those identities together! ๐Ÿ’ช
๐Ÿงฎ Mathematics

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crawford.patrick4 Dec 30, 2025

๐Ÿ“š Understanding Sum and Difference Identities

Sum and difference identities are trigonometric identities that allow you to express trigonometric functions of sums or differences of angles in terms of trigonometric functions of the individual angles. They are essential tools in pre-calculus for simplifying expressions, solving equations, and proving other identities. Let's dive in!

โž•โž– Definition of Sum Identities

Sum identities express trigonometric functions of the sum of two angles, say $A$ and $B$, in terms of trigonometric functions of $A$ and $B$ individually.

๐Ÿ“๐Ÿงญ Definition of Difference Identities

Difference identities express trigonometric functions of the difference of two angles, say $A$ and $B$, in terms of trigonometric functions of $A$ and $B$ individually.

๐Ÿ†š Sum vs. Difference Identities: A Comparison

Feature Sum Identities Difference Identities
Sine $\sin(A + B) = \sin A \cos B + \cos A \sin B$ $\sin(A - B) = \sin A \cos B - \cos A \sin B$
Cosine $\cos(A + B) = \cos A \cos B - \sin A \sin B$ $\cos(A - B) = \cos A \cos B + \sin A \sin B$
Tangent $\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$ $\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
Operation Deals with the addition of angles. Deals with the subtraction of angles.

๐Ÿ”‘ Key Takeaways

  • ๐Ÿงฎ Remember the formulas: Accurate application is crucial for solving problems.
  • ๐Ÿ”„ Practice substitution: The more you practice, the easier it will be to recognize when and how to apply these identities.
  • ๐Ÿง Be mindful of signs: A small sign error can lead to a completely wrong answer.

๐Ÿ“ Example Problems Solved

Let's walk through some examples to see these identities in action.

โœ๏ธ Problem 1: Simplify $\sin(75^{\circ})$

We can write $75^{\circ}$ as $45^{\circ} + 30^{\circ}$. Using the sine sum identity:

$\sin(75^{\circ}) = \sin(45^{\circ} + 30^{\circ}) = \sin 45^{\circ} \cos 30^{\circ} + \cos 45^{\circ} \sin 30^{\circ}$

$= (\frac{\sqrt{2}}{2})(\frac{\sqrt{3}}{2}) + (\frac{\sqrt{2}}{2})(\frac{1}{2}) = \frac{\sqrt{6} + \sqrt{2}}{4}$

๐Ÿ“ Problem 2: Simplify $\cos(15^{\circ})$

We can write $15^{\circ}$ as $45^{\circ} - 30^{\circ}$. Using the cosine difference identity:

$\cos(15^{\circ}) = \cos(45^{\circ} - 30^{\circ}) = \cos 45^{\circ} \cos 30^{\circ} + \sin 45^{\circ} \sin 30^{\circ}$

$= (\frac{\sqrt{2}}{2})(\frac{\sqrt{3}}{2}) + (\frac{\sqrt{2}}{2})(\frac{1}{2}) = \frac{\sqrt{6} + \sqrt{2}}{4}$

๐Ÿงฎ Problem 3: Simplify $\tan(105^{\circ})$

We can write $105^{\circ}$ as $60^{\circ} + 45^{\circ}$. Using the tangent sum identity:

$\tan(105^{\circ}) = \tan(60^{\circ} + 45^{\circ}) = \frac{\tan 60^{\circ} + \tan 45^{\circ}}{1 - \tan 60^{\circ} \tan 45^{\circ}}$

$= \frac{\sqrt{3} + 1}{1 - \sqrt{3}} = \frac{(\sqrt{3} + 1)(1 + \sqrt{3})}{(1 - \sqrt{3})(1 + \sqrt{3})} = \frac{4 + 2\sqrt{3}}{-2} = -2 - \sqrt{3}$

๐Ÿค” Practice Quiz

Test your knowledge with these practice questions!

  1. โ“ Simplify $\sin(15^{\circ})$
  2. โ“ Simplify $\cos(75^{\circ})$
  3. โ“ Simplify $\tan(15^{\circ})$
  4. โ“ Find the exact value of $\sin(165^{\circ})$
  5. โ“ Find the exact value of $\cos(105^{\circ})$
  6. โ“ Find the exact value of $\tan(195^{\circ})$
  7. โ“ Simplify $\sin(x + \frac{\pi}{2})$

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