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lisa_davis 9h ago โ€ข 0 views

Calculating Local Truncation Error in Euler's Method: A How-To Guide

Hey everyone! ๐Ÿ‘‹ I'm trying to wrap my head around local truncation error in Euler's method. It's kinda confusing! Can anyone break it down in a simple way, maybe with an example? I'd really appreciate it! ๐Ÿ™
๐Ÿงฎ Mathematics

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tashataylor2002 Jan 5, 2026

๐Ÿ“š Understanding Local Truncation Error in Euler's Method

Euler's method is a numerical technique used to approximate the solution of ordinary differential equations (ODEs). However, each step introduces a small error, called the local truncation error. This error arises because Euler's method uses a linear approximation of the solution.

๐Ÿ“œ History and Background

Euler's method, named after Leonhard Euler, is one of the earliest and simplest numerical methods for solving ODEs. It forms the basis for more advanced techniques. The method's simplicity makes it useful for understanding fundamental concepts in numerical analysis.

โœจ Key Principles

  • ๐Ÿ“ Definition: The local truncation error (LTE) is the error introduced in a single step of Euler's method, assuming that the solution at the previous step is exact.
  • โœ๏ธ Formula: For the ODE $\frac{dy}{dx} = f(x, y)$ with initial condition $y(x_0) = y_0$, Euler's method approximates the solution at $x_{i+1}$ as $y_{i+1} = y_i + h f(x_i, y_i)$, where $h$ is the step size.
  • ๐Ÿ“ Taylor Series: The exact solution can be expressed using a Taylor series expansion: $y(x_{i+1}) = y(x_i) + h y'(x_i) + \frac{h^2}{2!} y''(x_i) + O(h^3)$.
  • ๐Ÿงฎ LTE Calculation: The LTE is the difference between the exact solution and the Euler's method approximation: $LTE = |y(x_{i+1}) - y_{i+1}| = |\frac{h^2}{2} y''(\xi)|$, where $\xi$ is some value between $x_i$ and $x_{i+1}$. This shows that the LTE is proportional to $h^2$.
  • ๐Ÿ“‰ Order of Accuracy: Euler's method is first-order accurate because the LTE is $O(h^2)$, and the global error (accumulated error over multiple steps) is $O(h)$.

โš™๏ธ Practical Example

Consider the ODE $\frac{dy}{dx} = y$ with initial condition $y(0) = 1$. We want to approximate $y(0.1)$ using Euler's method with a step size of $h = 0.1$.

  1. Euler's Method Approximation: $y_{1} = y_0 + h f(x_0, y_0) = 1 + 0.1 * 1 = 1.1$.
  2. Exact Solution: The exact solution is $y(x) = e^x$, so $y(0.1) = e^{0.1} \approx 1.10517$.
  3. Local Truncation Error: $LTE = |1.10517 - 1.1| = 0.00517$.

๐Ÿ’ก Tips for Minimizing LTE

  • โฌ‡๏ธ Reduce Step Size: Decreasing the step size $h$ reduces the LTE, but it also increases the number of computations.
  • ๐Ÿ“ˆ Use Higher-Order Methods: Methods like the Runge-Kutta methods have higher orders of accuracy and smaller LTE.
  • ๐Ÿง Error Estimation: Estimate the LTE at each step and adjust the step size dynamically to maintain a desired level of accuracy.

๐Ÿ“ Conclusion

Understanding local truncation error is crucial for using Euler's method effectively. By recognizing the sources of error and employing strategies to minimize it, you can obtain more accurate numerical solutions to ODEs. Euler's method, while simple, provides a foundation for more advanced numerical techniques.

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