1 Answers
📚 Quick Study Guide
- ⚖️ The Common Ion Effect describes the decrease in solubility of a sparingly soluble salt when a soluble salt containing a common ion is added to the solution.
- ➗ To calculate the solubility of a salt in the presence of a common ion, set up an ICE table similar to solubility equilibrium problems.
- 📝 Remember that the initial concentration of the common ion must be included in the 'I' row of the ICE table.
- ➕ The solubility ($s$) represents the change in concentration of the ions from the sparingly soluble salt as it dissolves.
- 🧮 Use the $K_{sp}$ expression to solve for $s$: $K_{sp} = [M^{n+}]^m[X^{m-}]^n$, where $M$ is the cation, and $X$ is the anion.
- 🌡️ The common ion effect is an application of Le Chatelier's principle; adding a common ion shifts the equilibrium towards the undissolved salt.
- 💡 Approximations can often be made if the $K_{sp}$ value is small, simplifying the algebra: Assume $x$ is negligible compared to the initial concentration of the common ion.
🧪 Practice Quiz
-
What is the common ion effect?
- The increase in solubility of a salt due to a common ion.
- The decrease in solubility of a salt due to a common ion.
- The increase in the $K_{sp}$ value.
- The decrease in the $K_{sp}$ value.
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Which of the following salts is least soluble in a 0.1 M solution of NaCl? Given: $K_{sp}$(AgCl) = $1.8 \times 10^{-10}$
- AgBr ($K_{sp} = 5.0 \times 10^{-13}$)
- AgI ($K_{sp} = 8.3 \times 10^{-17}$)
- AgCl ($K_{sp} = 1.8 \times 10^{-10}$)
- AgCN ($K_{sp} = 2.2 \times 10^{-12}$)
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The solubility of $AgCl$ in pure water is $1.3 \times 10^{-5}$ M. What is the solubility of $AgCl$ in 0.10 M $NaCl$?
- $1.7 \times 10^{-9}$ M
- $1.3 \times 10^{-5}$ M
- $1.3 \times 10^{-6}$ M
- $1.8 \times 10^{-9}$ M
-
Which of the following statements is true regarding the common ion effect on the solubility of $Mg(OH)_2$ in a solution containing $NaOH$?
- The solubility of $Mg(OH)_2$ will increase.
- The solubility of $Mg(OH)_2$ will decrease.
- The solubility of $Mg(OH)_2$ will remain the same.
- The $K_{sp}$ of $Mg(OH)_2$ will increase.
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What is the effect of adding $NH_4Cl$ to a saturated solution of $NH_3$?
- Increases the concentration of $OH^-$
- Decreases the concentration of $OH^-$
- No effect on the concentration of $OH^-$
- Increases the concentration of $NH_3$
-
Calculate the molar solubility of $BaSO_4$ ($K_{sp} = 1.1 \times 10^{-10}$) in 0.10 M $Na_2SO_4$ solution.
- $1.1 \times 10^{-9}$ M
- $1.1 \times 10^{-10}$ M
- $1.0 \times 10^{-5}$ M
- $1.1 \times 10^{-8}$ M
-
Which of the following will decrease the solubility of $Ag_2CrO_4$ in water?
- Adding $HNO_3$
- Adding $AgNO_3$
- Adding $NH_3$
- Adding $KCl$
Click to see Answers
- B
- B
- D
- B
- B
- A
- B
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