rebecca519
rebecca519 3d ago • 10 views

How to Calculate Boiling Point Elevation: Worked Examples

Hey everyone! 👋 Let's tackle boiling point elevation. It can seem tricky, but with a solid understanding and some practice, you'll ace it. I've put together a quick study guide and a practice quiz to help you master this concept. Good luck! 🍀
🧪 Chemistry
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🧪 Quick Study Guide

  • 🌡️ Boiling point elevation is a colligative property, meaning it depends on the number of solute particles in a solution, not their identity.
  • ⚗️ The formula for boiling point elevation is: $$\Delta T_b = i \cdot K_b \cdot m$$, where:
    • $\Delta T_b$ is the boiling point elevation.
    • $i$ is the van't Hoff factor (number of particles the solute dissociates into).
    • $K_b$ is the ebullioscopic constant (boiling point elevation constant) of the solvent.
    • $m$ is the molality of the solution (moles of solute per kilogram of solvent).
  • 💧 Molality (m) is calculated as: $$m = \frac{\text{moles of solute}}{\text{kilograms of solvent}}$$.
  • 🔑 Remember to always use the correct units: $K_b$ is in °C kg/mol, and molality is in mol/kg.
  • 💡 The new boiling point of the solution is: $$T_{b(solution)} = T_{b(pure \ solvent)} + \Delta T_b$$.

Practice Quiz

  1. Question 1: What is a colligative property?
    1. A) A property that depends on the type of solute.
    2. B) A property that depends on the amount of solvent.
    3. C) A property that depends on the number of solute particles.
    4. D) A property that depends on the identity of the solvent.
  2. Question 2: What does the van't Hoff factor (i) represent?
    1. A) The molality of the solution.
    2. B) The boiling point elevation constant.
    3. C) The number of particles a solute dissociates into.
    4. D) The change in temperature.
  3. Question 3: What is the formula for calculating molality (m)?
    1. A) $$m = \frac{\text{kilograms of solvent}}{\text{moles of solute}}$$
    2. B) $$m = \frac{\text{moles of solute}}{\text{liters of solution}}$$
    3. C) $$m = \frac{\text{moles of solute}}{\text{kilograms of solvent}}$$
    4. D) $$m = \frac{\text{grams of solute}}{\text{kilograms of solvent}}$$
  4. Question 4: If $K_b$ for water is 0.512 °C kg/mol, and you have a 1 molal solution of NaCl in water (i=2), what is the boiling point elevation?
    1. A) 0.256 °C
    2. B) 0.512 °C
    3. C) 1.024 °C
    4. D) 2.048 °C
  5. Question 5: What are the correct units for the ebullioscopic constant ($K_b$)?
    1. A) mol/kg
    2. B) °C/mol
    3. C) °C kg/mol
    4. D) kg/°C
  6. Question 6: You dissolve 58.44 grams of NaCl (i=2) in 1 kg of water. What is the molality of the solution? (Molar mass of NaCl = 58.44 g/mol)
    1. A) 0.5 m
    2. B) 1 m
    3. C) 2 m
    4. D) 0.1 m
  7. Question 7: If pure water boils at 100 °C, and a solution has a boiling point elevation of 1.5 °C, what is the boiling point of the solution?
    1. A) 98.5 °C
    2. B) 100 °C
    3. C) 101.5 °C
    4. D) 102 °C
Click to see Answers
  1. C
  2. C
  3. C
  4. C
  5. C
  6. B
  7. C

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