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aaron849 Jan 20, 2026 โ€ข 0 views

Cylindrical Shell Method: Horizontal Axis Definition Explained in Calculus

Hey everyone! ๐Ÿ‘‹ I'm struggling with the cylindrical shell method when the axis of rotation is horizontal. It's making my brain hurt! ๐Ÿคฏ Can anyone explain it in a simple way? I'm getting confused with setting up the integral. Any help would be greatly appreciated!
๐Ÿงฎ Mathematics

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โœ… Best Answer

๐Ÿ“š Cylindrical Shell Method: Horizontal Axis โ€“ A Comprehensive Guide

The cylindrical shell method is a powerful technique in calculus for calculating the volume of a solid of revolution. When the axis of revolution is horizontal, we integrate with respect to $y$ instead of $x$. This guide breaks down the concept with clear explanations and examples.

๐Ÿ“œ History and Background

The concept of finding volumes using infinitesimally thin slices dates back to Archimedes. The cylindrical shell method, as a formal technique, evolved as a refinement of these early ideas, providing an alternative to the disk and washer methods, especially when those methods become cumbersome.

  • ๐Ÿ‘ด๐Ÿป Ancient Roots: Archimedes' method of exhaustion laid the groundwork for integral calculus.
  • โš™๏ธ Calculus Development: The formalization of calculus by Newton and Leibniz provided the tools for defining the cylindrical shell method.
  • ๐Ÿ“ˆ Practical Application: The method became essential for solving volume problems where other techniques are less efficient.

๐Ÿ”‘ Key Principles: Horizontal Axis

When rotating a region around a horizontal axis, envision the cylindrical shells stacked horizontally. Here's how to set up the integral:

  • ๐Ÿ“ Radius: The radius of each cylindrical shell is the vertical distance from the axis of revolution to the curve, typically expressed as $r(y)$.
  • โฌ†๏ธ Height: The height of each shell is the horizontal length of the region at a given $y$-value, often written as $h(y)$. This is found by subtracting the left function from the right function: $h(y) = x_{right}(y) - x_{left}(y)$.
  • โž— Thickness: The thickness of each shell is $dy$, representing an infinitesimal change in $y$.
  • ๐Ÿ“ Volume of a Shell: The volume of a single cylindrical shell is given by $2 \pi r(y) h(y) dy$.
  • ๐Ÿงฎ Total Volume: To find the total volume, integrate the volume of the shells over the interval $[c, d]$ on the $y$-axis, where $c$ and $d$ are the limits of integration: $V = \int_{c}^{d} 2 \pi r(y) h(y) dy$.

โš™๏ธ Step-by-Step Guide

  1. โœ๏ธ Sketch the Region: Draw the region bounded by the given curves.
  2. ๐Ÿ”„ Identify the Axis of Revolution: Determine the horizontal line around which the region is rotated.
  3. โ†•๏ธ Express Functions in Terms of y: Rewrite any functions in terms of $y$ (i.e., $x = f(y)$).
  4. ๐Ÿ“ Determine the Radius, r(y): Find the distance from the axis of revolution to the variable $y$. If rotating around $y=k$, then $r(y) = |y-k|$.
  5. โ†”๏ธ Determine the Height, h(y): Find the difference between the right and left functions, $h(y) = x_{right}(y) - x_{left}(y)$.
  6. ๐Ÿ“ˆ Set up the Integral: Formulate the integral: $V = \int_{c}^{d} 2 \pi r(y) h(y) dy$.
  7. โž— Evaluate the Integral: Calculate the definite integral to find the volume.

๐ŸŒ Real-World Examples

Let's look at some practical applications:

  • ๐Ÿฅค Drinking Glass: Imagine a drinking glass formed by rotating a curve around the x-axis. The cylindrical shell method can calculate the glass's volume.
  • ๐Ÿบ Vase Design: The volume of a vase with a curved profile, rotated around a central axis, can be accurately determined.
  • ๐Ÿ”ฉ Machine Parts: Calculating the volume of complex machine parts with rotational symmetry.

๐Ÿ“ Example Problem

Find the volume of the solid formed by rotating the region bounded by $x = y^2$ and $x = 2y$ about the x-axis.

  1. โœ๏ธ Sketch: Draw the region bounded by the parabola $x = y^2$ and the line $x = 2y$.
  2. ๐Ÿ”„ Axis: Axis of revolution is the x-axis ($y=0$).
  3. โ†•๏ธ Functions in terms of y: Already done: $x = y^2$ and $x = 2y$.
  4. ๐Ÿ“ Radius: $r(y) = y - 0 = y$.
  5. โ†”๏ธ Height: $h(y) = 2y - y^2$.
  6. ๐Ÿ“ˆ Integral: $V = \int_{0}^{2} 2 \pi y (2y - y^2) dy = 2 \pi \int_{0}^{2} (2y^2 - y^3) dy$.
  7. โž— Evaluate: $V = 2 \pi [(\frac{2}{3}y^3 - \frac{1}{4}y^4)]_{0}^{2} = 2 \pi [(\frac{16}{3} - \frac{16}{4})] = 2 \pi (\frac{16}{3} - 4) = 2 \pi (\frac{4}{3}) = \frac{8 \pi}{3}$.

Therefore, the volume is $\frac{8 \pi}{3}$ cubic units.

โœ… Conclusion

The cylindrical shell method, when applied to horizontal axes, provides a robust method for volume calculation. By correctly identifying the radius, height, and limits of integration, you can master this technique and solve a wide range of problems. Remember to always visualize the cylindrical shells and ensure your functions are expressed in terms of $y$.

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